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Calculate MPH At The 60' | |
D= .5 x AxT^2 A == ft/sec^2 T=seconds D=distance in feet d/(.5 * t*t) = fps fps * .68181818 = mph? ---------------------- That last set of data I posted seemed to fit best to a 6th deg poly. The equation I came up with is: 6th Degree Polynomial Fit: y=a+bx+cx^2+dx^3... Coefficient Data: a = 0000067290643 b = 11.171725 c = 9.2796363 d = 0.16608009 e = -0.071281314 f = 0.0051347964 g = -0.00012727154 The positions matched exactly. Taking the 1st derivative, the velocities are as follows: 8.838 sec 87.94 MPH versus the reported 86.13 MPH 12.908 sec 108.84 MPH versus the reported 108.55 MPH The 0-60MPH time then comes out to be 4.506 sec.