Q: How Fast Does the Man Fall?If a 180 lb. man drops 1150 feet from a building, how many km per hour will he be going when he hits the ground?A:In these physics problems, the weight of the man is unimportant. The problem can be solved without knowing his weight. The formula used is: 2 2 (vf) = (v0) + 2*a*(delta y) where: vf is the velocity of the object when it hits the ground (or final velocity) vo is the object's original velocity a is the acceleration due to gravity delta y is how far it falls 2 2 vf = (0) + 2*(32 ft/sec^2)*(1150 ft) 2 vf = 73600 ft^2 / sec^2 now take the square root of vf^2 to get vf... vf = 271.29 ft/sec 271.29 ft/sec X .6818182 = 184.97 MPH